(MATH 114N Week 3 Test 1 Review Attempt 1)
1. Question: Factor the trinomial completely.
s2 + 5s + 66
- Question: Solve.
v2 – 30v + 29 = 0
- Question: Factor by grouping.
x3 + 5x2 + 6x + 30
x3 + 5x2 + 6x + 30 = (x + 5)(x2 + 6)
- Question: Complete the factoring.
2x3 + 14x2 + 24x
- Question: Complete the factoring.
12a3 – 26a2 + 4a = 2a( _)
= 2a( ) ( )
- Question: Mary works due north of home. Her husband Juan works due east. They leave for work at the same time. By the time Mary is 5 miles from home, the distance between them is one mile more than Juan’s distance from home. How far from home is Juan?
- Question: Factor the trinomial.
r2 + 6r + 5
- Question: Factor the following polynomial by grouping.
s2 + 11sg + 28g2
- Question: Solve using the zero factory property.
(2w + 5)(w + 4) = 0
- Question: Factor completely.
64s2 + 25g2
- Question: Factor the trinomial by grouping.
8m2 – 2m – 3
- Question: Factor completely.
s2 + 4
- Question: Which of the following are differences of square.
a2 – 16, y2 + 4, 8m2 – 25, 9x2 – 1
- Question: Factor the special product.
25r2 – 30r + 9
- Question: Find the greatest common factor (GCF) of 24x and 9.
- Question: The area of parallelogram is given by the A = bh.
The area of parallelogram on the right side is 45 sq.units.
Find its base and height.
- Question: If an object is projected upward with an initial velocity of 128 ft per sec, its height h after t second is h = -6t2 + 128t. Find the height of the object after 4 seconds.
- Question: What polynomial can be factored as (a + 9)(a + 5).
- Question: Factor. Note that the middle term has already been split.
40r2 – 35r + 24r – 21
40r2 – 35r + 24r – 21 = (5r + 3)(8r – 7)
- Quesution: Factor completely.
36x2 – 84xy + 49y2
- Question: Complete the factoring.
2a2 + 4a – 16 = 2( )( )
2a2 + 4a – 16 = 2(a – 2)(a + 4)
- Question: The middle term of the trinomial has been rewritten. Now factor by grouping.
10r2 + 31rs + 15s2 = 10r2 + 25rs + 6rs + 15s2
10r2 + 25rs + 6rs + 15s2 = (2r + 5s)(5r + 3s)
- Question: Complete the factoring.
2y + 30 = 2( )
- Question: The product of two consecutive integers is 1 more than their sum. Find the integers.
- Question: Factor.
20b2 + 5b
- Question: A garden has a shape of a right triangle with one leg of 8 meters longer than the other. The hypotenuse is 8 meters less than twice the length of the shorter leg. What is the length of the shorter leg.
- Question: A garden has a shape of a right triangle with one leg of 6 meters longer than the other. The hypotenuse is 6 meters less than twice the length of the shorter leg. What is the length of the shorter leg.
- Question: A garden has a shape of a right triangle with one leg of 4 meters longer than the other. The hypotenuse is 4 meters less than twice the length of the shorter leg. What is the length of the shorter leg.
- 29. Question: A garden has a shape of a right triangle with one leg of 2 meters longer than the other. The hypotenuse is 2 meters less than twice the length of the shorter leg. What is the length of the shorter leg.
- Question: Which of the following are differences of squareds?
a2 – 16, y2 + 4, 8m2 – 25, 9x2 – 1